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This value determines what happens in the event the supplied path is invalid. This optional path mode can be a value of either lax or strict. The path argument (if supplied) can include an optional path mode component. The path argument is optional (if you don’t provide it, the whole JSON document is returned). Where expression is the JSON string expression, and path is the object or array that you want to extract from that expression. The syntax goes like this: JSON_QUERY ( expression ) You can also provide a second (optional) argument to specify the object or array to extract. To use this function, you provide the JSON expression as an argument. In my I’ll talk about storing JSON string in a table and doing some hands-on with it.When using JSON with SQL Server, you can use the JSON_QUERY() function to extract an object or an array from a JSON string. JSON_Value (p.value, '$.UnitPrice') as UnitPriceĬROSS APPLY OPENJSON (c.value, '$.OrderDetail') as p JSON_Value (p.value, '$.ProductID') as ProductID, JSON_Value (c.value, '$.CustomerID') as CustomerID, JSON_Value (c.value, '$.OrderID') as OrderID, Using JSON_Value() with OPENJSON() function: This can be done by CROSS APPLYing the JSON child node with the parent node and using the JSON_Value() function, like shown below: Ok, so by using the key path and the array position we can get the child elements value in our Query result-set by using above 2 methods.īut instead of having them in separate columns how about pulling them in separate rows, this will also make your query dynamic as you would not know the number of child-elements before hand, right? ProductID2 INT '$.OrderDetail.ProductID', UnitPrice1 INT '$.OrderDetail.UnitPrice',
#SQL SERVER JSON QUERY NODES COUNT FULL#
You can also specify the child elements with full path by using the dollar sign “$” inside the WITH() clause (instead at column level above), like below: OrderIDĜustomerID ProductID1 UnitPrice1 ProductID2 UnitPrice2 In this case what you have to do is, use the array positions with square brackets (“”) in your query and call out separate columns for each child element, like below: Because, here you are having array of child elements with OrderDetail node (notice the square-bracket after “OrderDetail”: node), thus the Query is not able to find the key on the path. Instead you get ProductID & UnitPrice column values as NULL. You might be expecting 2 rows with same OrderID & CustomerID, with different ProductID & UnitPrice, right? Using OPENJSON() function:īut, if you have more than one nested elements the same query will give just 1 row with NULL values under the child columns, like this. Here, we have just one nested element, and the OPENJSON() function will get you the child elements values:
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We will see usage of both the functions in our example below: – JSON_Value() Scalar function: returns a value from JSON on the specified path.
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– OPENJSON() Table valued function: parses JSON text and returns rowset view of JSON. Native JSON support in SQL Server 2016 provides you few functions to read and parse your JSON string into relational format and these are:
#SQL SERVER JSON QUERY NODES COUNT HOW TO#
Today in this post I’ll talk about how to read/parse JSON string with nested array of elements, just like XML. In my I discussed about how to Import or Read a JSON string and convert it in relational/tabular format in row/column from.